JSON for Modern C++  3.9.1

◆ get() [2/6]

template<template< typename U, typename V, typename... Args > class ObjectType = std::map, template< typename U, typename... Args > class ArrayType = std::vector, class StringType = std::string, class BooleanType = bool, class NumberIntegerType = std::int64_t, class NumberUnsignedType = std::uint64_t, class NumberFloatType = double, template< typename U > class AllocatorType = std::allocator, template< typename T, typename SFINAE=void > class JSONSerializer = adl_serializer, class BinaryType = std::vector<std::uint8_t>>
template<typename BasicJsonType , detail::enable_if_t< !std::is_same< BasicJsonType, basic_json >::value &&detail::is_basic_json< BasicJsonType >::value, int > = 0>
BasicJsonType nlohmann::basic_json< ObjectType, ArrayType, StringType, BooleanType, NumberIntegerType, NumberUnsignedType, NumberFloatType, AllocatorType, JSONSerializer, BinaryType >::get ( ) const
inline

This overloads converts the current basic_json in a different basic_json type

Template Parameters
BasicJsonType== basic_json
Returns
a copy of *this, converted into
Template Parameters
BasicJsonType
Complexity^^ Depending on the implementation of the called from_json()
method.
Since
version 3.2.0

Definition at line 19359 of file json.hpp.